reverse roulette
reverse martingale??
roulette What if you bet a dollar on red, and after winning twice, but the bet of a dollar after a waste of time …. hit me up to the table … sitting, I'm not the dealer wins but I'm also chasing losses .. granted, I'm probably just rack up drinking whiskey malt per hundred dollars of the bet to cover the standard house edge, but is only a small waterfall in the comfortable chairs provided
So let's see if I have that right. You can bet a dollar. If you win, you bet $ 2. If he wins again, 4, then 8, then 16, then 32, 64, 128, 256, 512, 1024 and then again bet $ 2048, which is probably the maximum most tables. Do I have it right? And then and only then you walk away from the table. Only after having beaten 12 times in a row??? If I did it my right to mathematics, based on a double zero and congratulations on a single zero wheel, then. About once every 7837 times you tried this, you would earn $ 4,095. All other times, you lose $ 1. That figure seems a little high for me. I think he would win a little more often than that. Someone please correct my account if you can. (EDIT – Actually I think the math is correct.) So if I'm right, you win $ 4095 once for each $ 7,836 that you lost. **** **** Realistically though, most places have at least 5 or $ 10. If you started at $ 10 you would win 10, then 20, then 40, then 80, then 160, 320, 640, 1,280, and if they let you bet, you would earn U.S. $ 2560 final. Your total would be $ 5120 or $ 5110 in earnings. You affect this much more often: Once in every 833 times he tried! Again I would like to congratulate you on this idea. Lose $ 8,320 for every time you won $ 5,120. Oh … perhaps requiring no congratulations???
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