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In four games on a roulette wheel, what is the probability that the ball lands on red?

In four games on a roulette wheel, what is the probability that the ball lands in red? A successful, s in Bernoulli trials is often derived from the collection of results. For example, a wheel American Roulette consists of 38 numbers, of which 18 are black, 18 are red, and 2 are green. When the wheel spins the wheel, the ball is equally likely to land in any of the 38 numbers. If you are interested in the number of falls in each game ball in the roulette wheel has 38 possible outcomes. Suppose however, you are betting on red. Then you are only interested in if the ball lands on a red number or not. So the stakes are a red successive sequence of Bernoulli trials with success probability 18/38. In four games on a roulette wheel, what is the probability that the ball lands in red) exactly double b) at least once

going to do part (b) qb first P [no network] = [20/38] [20/38] [20/38] [20/38] = (10/19) ^ 4, P [al least one network] = 1 – (10/19) ^ 4 = 0.9233 ———– qa February 1 red routes RRxx can happen is with a probability (9.19) ^ 2 * (10/19 ) ^ 2, but the 2 cells can occur in 4 '/ 2! 2! = 6 sequences RxRx RRxx RxxR xRRx xRxR xxRR to reqd. probability = 6 * (9.19) ^ 2 * (10/19) ^ 2 = 3729 ———–